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Given f(x) =|x|. Explain the difference between the graphs of g(x)=|x-3| and h (x) = |x| -3?
|x-3| is the abolsute value of x-3, so it will never be positive even when X is 2 or less. |X|-3, however, can have a negative value. So at 2 |X-3| is 1, but |X|-3 is -1. As a result, h(x) will be slightly offset.
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